Re: [ST] Bring on the cold!!!...this enough?

[Bryce <bster13@xxxxxxxxx>]

Well there was my first mistake...

28.6v/6000RPM = x/4000RPM, x=19.04v @ 4,000 RPM

should read...

28.6a/6000RPM = x/4000RPM, x=19.04a @ 4,000 RPM

so in this equation:

Watts = Amps x Volts

W = 19.04a x 14v (constant)

hehe...damn typos!

And based on what enrico said, it won't be a constant
14v, I'm guessing more around 13.5 from what I
remember when I measured this summer at a constant RPM
somewhere above idle.

Thanks,

Bryce

- --- "Anderson, Neil G (CPR)" <andersng@xxxxxx> wrote:
> Bryce wrote:
> 
> > 28.6v/6000RPM = x/4000RPM, x=19.04v @ 4,000 RPM
> 
> As Enrico says, I think you'll find the alternator
> output voltage is more
> constant across the rev range, only at idle will it
> drop significantly below
> around 14 volts
> 
> >- - 60 watt headlight (on high)
> >- - 42 watts tailights (21 each)
> >- - 24 watts heated grip kit on high
> >- - 50 watts homemade heated vest (buid to meet
> heat
> >needs, may draw less)
> 
> You need to allow current for the ECU/ignition,
> instruments etc
> 
> > Is 24.2 watts left to charge the battery correct?
> 
> That isn't much of a safety margin to keep the
> battery charged
> 
> Neil (not a geek thanks, but I used to be an
> electrical engineer!)
> 
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